**A**

First of all, we need to find the average rate if disappearence for A, where the formula is -ΔC/Δt

First rate (A) = -ΔC/Δt = – (0.430-0.720)/(196-0) = 1.48 * 10^{-3} mol/(L*s)

Second rate (A) = -Δc/Δt = – (0.140-0.430)/(392-196) = 1.48 * 10^{-3} mol/(L*s)

**As we can see, the average rate of A equals 1.48 * 10 ^{-3} mol/(L*s)**

Provided that A⟶2B,

The average rate of change (B) = 1.48 * 10^{-3} * 2 = 2.96 * 10^{-3 }mol/(L*s)

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