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Q

Chemistry help ASAP! Please help me solve this!

The task as follows: Ut's given two enthalpies of reaction N2(g)+2O2(g)-->2NO2(g) ?H°1=+66.4kJ 2NO(g)+O2(g)-->2NO2(g). ?H°2=-114.2kJ I need to calculate the enthalpy for the reaction N2(g)+O2(g)-->2NO(g) Please, help me solve this before tomorrow test!
A

Solution:
N2(g)+2O2(g)–>2NO2(g)   ?H°1=+66.4kJ
2NO2(g)–>  2NO(g)+O2(g)   ?H°2=+114.2kJ

Add the rxns to get an answer:

N2(g)+2O2(g)–>2NO2(g) ?H°1=+66.4kJ
2NO2(g)–> 2NO(g)+O2(g) ?H°2=+114.2kJ

So the answer is

N2(g) +  O2(g)  –> 2NO(g)

66.4kJ + 114.6 kJ = 181kJ.

3 years ago
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